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Home/ Questions/Q 28577
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Asked: 30/10/20262026-10-30T09:03:33+00:00 2026-10-30T09:03:33+00:00In: Programmers

Robot Bounded in Circle: Why Does One Pass Work, and What Is the Python Solution?

Coding interview practice · LeetCode 1041

A robot begins at the origin, facing north. It repeats the same instruction string forever. How can we decide, after simulating that string just once, whether its entire path stays inside a fixed circle?

GMove forward one unit
LTurn left by 90°
RTurn right by 90°

Python 3 · Simulation · Geometric reasoning · O(n) time

The answer below develops the proof, walks through examples and gives a tested Python implementation. Practice the original problem on LeetCode ↗

Qaskme editorial coding Q&A, published at the site owner’s request with an AI-assisted explanation and independently tested code. Independent interview practice material.

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    1. 2026-10-30T09:03:33+00:00Added an answer on 30/10/2026 at 9:03 am

      Editorial answer · Explanation + Python solution

      The one-pass test

      The path is bounded when one complete pass ends at the origin, or the robot finishes facing a direction other than north.

      You only need the final position and direction. There is no need to store every visited point or run the instructions indefinitely.

      Why this works

      Think of one complete instruction string as a single movement pattern. Each repetition has the same shape, rotated to match the robot’s starting direction.

      After one pass What happens next? Bounded?
      Back at the origin There is no net displacement. Repeating the finite pattern stays within a fixed area, even if its orientation changes. Yes
      Away from the origin, facing north Every pass adds the same nonzero displacement in the same direction. The robot drifts farther away. No
      Away from the origin, facing south The next pass is rotated by 180°. Its displacement cancels the first pass, returning the robot to the origin after two passes. Yes
      Away from the origin, facing east or west Four passes produce four rotated displacements. Opposite displacements cancel, and the robot returns to the origin. Yes

      For the last case, the displacement vectors are the same vector rotated by 0°, 90°, 180° and 270°. Their sum is zero. Since the repeating route consists of finitely many steps, a circle can enclose the whole route.

      Bounded does not mean circular. The robot can follow a square, a line segment or another repeating path. The requirement is that its full route fits inside some fixed circle.

      Python 3 solution

      Represent north with the direction vector (0, 1). A left turn changes (dx, dy) to (-dy, dx); a right turn changes it to (dy, -dx).

      Python 3 · LeetCode format
      class Solution:
          def isRobotBounded(self, instructions: str) -> bool:
              x, y = 0, 0
              dx, dy = 0, 1  # Start facing north.
      
              for move in instructions:
                  if move == "G":
                      x, y = x + dx, y + dy
                  elif move == "L":
                      dx, dy = -dy, dx
                  else:  # The remaining valid command is "R".
                      dx, dy = dy, -dx
      
              return (x == 0 and y == 0) or (dx, dy) != (0, 1)

      Command correction: LeetCode uses G for “go forward”. If an assessment variant uses S instead, change that comparison to match its statement. Do not use S when submitting to this LeetCode problem.

      Examples

      Instructions One-pass result Answer
      GGLLGG Returns to (0, 0), facing south. true
      GG Ends at (0, 2), still facing north. false
      GL Ends at (0, 1), facing west. true

      A closer look at GL

      Each pass moves forward once and turns left. The end states show how a changed heading closes the route:

      Pass Position Facing
      1 (0, 1) West
      2 (-1, 1) South
      3 (-1, 0) East
      4 (0, 0) North

      Complexity and edge cases

      • Time: O(n), where n is the instruction-string length. Each command is processed once.
      • Extra space: O(1), using only position and direction variables.
      • Turns only: bounded, because the robot never leaves the origin.
      • Forward moves only: unbounded for a nonempty string.

      Code verification: checked against all 9,840 valid command strings of lengths 1–8, eight explicit examples and four maximum-length cases. The independent reference simulator executes four full passes and checks for a return to the origin.

      Problem reference: LeetCode 1041 — Robot Bounded In Circle. The explanation and implementation here are Qaskme’s AI-assisted editorial practice material.

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